x^2+9,7^2=(2x)^2

Solution for x^2+9,7^2=(2x)^2 equation:

x^2+9.7^2=(2x)^2

We move all terms to the left:

x^2+9.7^2-((2x)^2)=0

determiningTheFunctionDomain
x^2-2x^2+9.7^2=0

We add all the numbers together, and all the variables

-1x^2+94.09=0

a = -1; b = 0; c = +94.09;
Δ = b2-4ac
Δ = 02-4·(-1)·94.09
Δ = 376.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{376.36}}{2*-1}=\frac{0-\sqrt{376.36}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{376.36}}{2*-1}=\frac{0+\sqrt{376.36}}{-2}
=\frac{\sqrt{}}{-2}
$